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UNO [17]
3 years ago
10

Write an expression for the cost of 1 uniform, add $13, $11 and $8 .

Mathematics
2 answers:
Liula [17]3 years ago
7 0

Answer:

Hey there!

Let the cost of one uniform be c, so the expression becomes

c+13+11+18

Thus, we have c+42

Hope this helps :)

Genrish500 [490]3 years ago
4 0

Answer:

32

Step-by-step explanation:

13+11+8=32

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The answer is 7 I think
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3 years ago
Two airplanes leave an airport at the same time, the first headed due north and the second at a bearing of N42^ E . At 2:00PM, t
Leno4ka [110]

Answer:

The two airplanes are about 330miles apart.

Step-by-step explanation:

The diagram interpreting the question has been attached to this response.

As shown in the diagram,

i. the airplanes leave at point C.

ii. at 2.00pm the first and second airplanes are at points A and B respectively, where they are 312miles and 487miles away from the starting point C in directions due north and N42E from the point C.

iii. the points A, B and C form a triangle with sides a, b and c.

To solve for the value of c which is the distance between the two planes at 2.00pm, the cosine rule is used.

c² = a² + b² - 2abcosC            --------------(i)

where;

b  = 312miles

a = 487miles

C = 42°

Substitute these values into equation (i) and solve as follows;

c² = (487)² + (312)² - 2(312)(487)cos(42)

c² = (237169) + (97344) - 303888cos(42)

c² = (237169) + (97344) - 303888(0.7431)

c² = 334513 - 225819.1728

c² = 108693.8272

<em>Take the square root of both sides</em>

√c² = √108693.8272

c = 329.69

c ≅ 330miles

Therefore, the two airplanes are far apart by 330miles

3 0
3 years ago
How do i do this?....... ​
iris [78.8K]

Order of operations (from high priority to low priority):

Parentheses

Exponents

Multiplications/Division

Addition/Subtraction

All in left to right.

2 ÷ (5 + 3)⁻¹ ÷ 4

2 ÷ (8)⁻¹ ÷ 4

2 ÷ 1/8 ÷ 4

16 ÷ 4

= 4

3 0
3 years ago
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MaRussiya [10]

Answer:

The mean for the second week is $2 less than the first and in percentage it is 22% less.

Step-by-step explanation:

The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:

sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75

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Since she spent 10 less in the second week the sum is:

sum2 = sum1 - 10 = 45 - 10 = 35

The mean for each week is:

mean1 = sum1/5 = 45/5 = 9

mean2 = sum2/5 = 35/5 = 7

difference = mean1 - mean2 = 9-7 = 2

difference(%) = [2/9]*100 = 0.22*100 = 22%

The mean for the second week is $2 less than the first and in percentage it is 22% less.

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So half of Nina's age is 10/2= 5. And since Greg is three years younger we subtract from 5 like so...
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5 0
3 years ago
Read 2 more answers
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