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AleksandrR [38]
3 years ago
11

The slope of the line below is 3. Use the coordinates of the labeled point to

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

y = 8+3x

Step-by-step explanation:

Remember that the equation of the line is

y-y_0 = m*(x-x_0)

in this case we have

y-8 = 3(x-0)

that is because

y_0 = 8, x_0 = 8 , m = 3

You might be interested in
Urn I contains three red chips and one white chip. Urn II contains two red chips and two white chips. One chip is drawn from eac
Lelechka [254]

Answer:

0.7

Step-by-step explanation:

The Probability of Chips in Urn 1

P(R) = 3/4

P(W) = 1/4

The Probability of Chips in Urn 2

P(R) = 1/2

P(W) = 1/2

The problem can be solved using probability tree method. The probability tree of the given question is attached with the answer.

The Probability tree shows the exchange of chips firstly and then the final probability of Red Chips and White Chips in Urn 1.

To find the final answer we can sum up the probabilities of the branches which are ticked in the diagram.

Probability of Branch 1 (ticked in diagram)

3/4 x 3/5 x 3/4 = 0.3375

Probability of Branch 2 (ticked in diagram)

3/4 x 2/5 x 2/4 = 0.15

Probability of Branch 3 (ticked in diagram)

1/4 x 2/5 x 1 = 0.1

Probability of Branch 4 (ticked in diagram)

1/4 x 3/5 x 3/4 = 0.1125

Final Probability = 0.3375 + 0.15 + 0.1 + 0.1125

= 0.7 Answer

7 0
3 years ago
~~~20 POINTS~~~<br> Please answer this question!
dusya [7]
So,

We have 10 mayflies.

Their mean lifespan is 4 hours.  That means that if you add the lifespans of all 10 mayflies and then divide the result by 10, you will get 4.

They have a MAD of 2 hours.  MAD stands for Mean Absolute Deviation (From the Mean, so it's really MADFM :P).  Once you get the mean, which we know is 4, you take the absolute value of the difference between the mean and each mayfly's lifespan, add those differences up, and divide the result by the number of mayflies (10).  Kind of complicated.

So, we can start with the first and second criteria, which is that there are 10 mayflies and their mean is 4 hours.  Therefore, all of their lifespans could be 4 hours.

4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 <span>+ 4 = 40
40/10 = 4
4 is the mean.

Of course, it could also be:
3 + 3</span> + 3 + 3 + 3 + 5 + 5 + 5 + 5<span> + 5 = 40
40/10 = 4
4 is still the mean.

Now that we know the solution set (infinite) for the first and second criteria, we are ready to factor in the third criterion, which is that the MAD is 2 hours.

Once again, to find the MAD, </span><span>you take the absolute value of the difference between the mean and each mayfly's lifespan, add those differences up, and divide the result by the number of mayflies (10).

The MAD of the first set of solutions I gave is 0, because all of the numbers were exactly on the mean.

Let's find the MAD of the second set of solutions I gave.

</span>3 + 3 + 3 + 3 + 3 + 5 + 5 + 5 + 5<span> + 5
</span>
All ten numbers are exactly 1 hour away from the mean.  Therefore, we will add up those differences and divide those differences by the number of mayflies.

1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1<span> + 1 = 10
10/10 = 1
The MAD for this set is 1.  However, we need the MAD to be 2 hours.  To do this, we just need to make all the differences 1 more.

2 + 2</span> + 2 + 2 + 2 + 6 + 6 + 6 + 6<span> + 6

This time, each number is 2 hours away from the mean.

2 + 2</span> + 2 + 2 + 2 + 2 + 2 + 2 + 2<span> + 2 = 20
20/10 = 2

This is a valid solution set that meets all three criteria.

The second question is actually just asking us to add another criterion: make one of the mayflies live for 1 day, or 24 hours.  So we just need to change the last one to 24, right?  Wrong.  You see, we will need to adjust the other numbers so that the mean and the MAD stay the same.  Since all of the numbers added to 40 in our solutions, we will just change the other numbers so that the mean will stay the same.

40 - 24 = 16

That means that the other 9 mayflies will live a total of 16 hours.  Dividing 16 by 9 tells us how long each mayfly has to live.

So our new set is:
</span>\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+\frac{16}{9}+24=40
<span>
40/10 = 4

Amazing!  Our mean is still 4.

Now, what is the MAD?

MAD = </span>2\ or\  \frac{18}{9}

Let's see if it still meets this criterion.

\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+\frac{2}{9}+ \frac{162}{9} = 20

There IS a problem.  Can we increase some of the numbers so that they are closer to the mean (decreasing the MAD) while decreasing some of the other numbers (to keep the mean constant)?  No.  That will change the mean.  So the answer to that question is no.

NO!!!!!!
6 0
3 years ago
What is the equation of the line with a slope of 2 through (–4, 6) in point-slope form?
Sloan [31]
In point-slope form, the equation is :

Y-6=2(x+4)

Hope this helps✨❤️
7 0
3 years ago
Each of the 10 students in the baking club made 2 chocolate cakes for a fundraiser. They all used the same recipe, using C cups
8090 [49]

Answer:

The expression is C/20 cups of flour in one cake

Step-by-step explanation:

* Lets explain how to solve the problem

- There are 10 students

- Each one made 2 chocolate cakes

- They all used the same recipe

- The total amount of flour is C cups

* Lets change these information to equation

∵ There are 10 students

∵ Each student made 2 cakes

∴ The total number of cakes = 10 × 2 = 20 cakes

∵ The total amount of flour for the twenty cakes is C cups

- To find the amount of flour in each cake divide the total amount

  of flour by the total number of the cakes

∴ The amount of flour in each cake = C/20

* The expression is C/20 cups of flour in one cake

7 0
4 years ago
There are 560 third- and fourth-grade students in King Elementary School. If there are 80 more third-graders than fourth-graders
Marianna [84]

Answer:

There are 200 4th grades and 360 third graders

Step-by-step explanation:

560/2=280-80=200 280+80=360

8 0
3 years ago
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