Answer:The final value of the expression is 149
2^8 . 5^-5 . 19^0)^-2
using PEMDAS
this = (2^8 * 1/5^5 * 1)^-2
= (5^5 / 2^8)^2
= 5^10 / 2^16
Answer:
The option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>
Step-by-step explanation:
As the domain of f(x) is the set of all real values except 7. So it can be written as follows:
Domain of f(x) = { x ∈ R | x ≠ 7}
As the domain of g(x) is the set of all real values except -3. So it can be written as follows:
Domain of g(x) = { x ∈ R | x ≠ -3}
It is a common rule that the domain of a composite function (gºf)(x) will be the set of those input x in the domain of f for which f(x) is in the domain of g.
So, the option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>
Keywords: domain, composite function
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Quadrant 1 Reason being all the positive are housed in quadrant 1
Answer:
25
Step-by-step explanation:
Brainliest please I haven't gotten it before
-1 17/20 and -1 8/10 can be compared easily if we give them common denominators. If we multiply the second fraction by 2, both fractions will have a denominator of 20.
8 * 2 = 16
10 * 2 = 20
New fraction: 16/20
-1 17/20 vs. - 1 16/20
-1 16/20 (-1 8/10) is greater. (For negative numbers, you can tell which one is greater by determining which one is closest to zero.)
