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Llana [10]
4 years ago
12

I need help please.. I really will appreciate it!

Mathematics
1 answer:
Rus_ich [418]4 years ago
3 0

Answer: the answer to this is B. 3x^2+4x+7 hopefully I'm correct

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HELPPPP PLSSS its for a math exam
patriot [66]

Answer:

pie is irrational nimber

8 0
3 years ago
Read 2 more answers
Help me pls.......... ​
CaHeK987 [17]

Answer:

x = 72 , y = 108

Step-by-step explanation:

2x and \frac{x}{2} are adjacent angles on a straight line and sum to 180° , that is

2x + \frac{x}{2} = 180 ( multiply through by 2 to clear the fraction )

4x + x = 360

5x = 360 ( divide both sides by 5 )

x = 72

--------------------------

\frac{x}{2} = \frac{72}{2} = 36

\frac{x}{2} and \frac{y}{3} are vertically opposite and are congruent , then

\frac{y}{3} = 36 ( multiply both sides by 3 )

y = 108

3 0
3 years ago
PLLLLLLLLLLZZZZZZZZZ
viktelen [127]

Answer: 12 - c

Step-by-step explanation:

Really, the expression is 96/8 - c

where 96/8 means The number of questions each child would have gotten if the grandma was fair, and - c means the amount of cookies fewer Cindy received.  Simplifying this, makes the expression 12 - c.

Hope it helps <3

3 0
3 years ago
Read 2 more answers
Please help…
tino4ka555 [31]

10

,

−

5

,

−

14

3

,

9

,

3.77

,

−

1

3

π

,

9

,

−

3.8

,

23

The natural numbers are:

10

,

9

,

9

,

23

The whole numbers are:

10

,

9

,

9

,

23

The integers are:

10

,

−

5

,

9

,

9

,

23

The rational numbers are:

10

,

−

5

,

−

14

3

,

9

,

3.77

,

9

,

−

3.8

,

23

The irrational number is:

−

1

3

π

 

7 0
3 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 270 day
dusya [7]

Answer:

a) 281 days.

b) 255 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 270, \sigma = 8

​(a) What is the minimum pregnancy length that can be in the top 8​% of pregnancy​ lengths?

100 - 8 = 92th percentile.

X when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 270}{8}

X - 270 = 1.405*8

X = 281

(b) What is the maximum pregnancy length that can be in the bottom 3​% of pregnancy​ lengths?

3rd percentile.

X when Z has a pvalue of 0.03. So X when Z = -1.88

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 270}{8}

X - 270 = -1.88*8

X = 255

8 0
4 years ago
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