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Tanya [424]
4 years ago
5

Find The constant of proportionality in the following equation: y=2/3 x

Mathematics
2 answers:
julia-pushkina [17]4 years ago
7 0
The constant of proportionality is 2/3x. This is because the equation states that the equation/line will travel constantly without speeding or slowing down.
serg [7]4 years ago
4 0

Answer:

2/3x

Step-by-step explanation:

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40+12=52. 180-52=128
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Can yall help plz.........................
vampirchik [111]

Answer:

6^-8 or 1/ 6^8

Step-by-step explanation:

When there is a fraction with the same base, then subtract the exponent of the denominator from the exponent of the numerator.

6^-3 / 6^5 = 6^(-3-5) = 6^-8

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Step-by-step explanation:

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4 years ago
Write a short story problem to represent the fraction 6/5
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5 0
3 years ago
Find the 100th and the nth term for each of the following sequences.80,140,200
Alina [70]

Answer

a(n) = 60n + 20

a(100) = 6020

Step-by-step explanation:

Given the following sequences

80, 140, 200

\begin{gathered} \text{The given sequence is }80,\text{ 140, 200} \\ \text{Step 1: find the common difference} \\ \text{common difference= next term - previous term} \\ \text{Common difference = 140 - 80} \\ \text{Common difference = 60} \\ \text{common difference = 200 - 140} \\ \text{common difference = 60} \\ \text{Hence, the common difference is 60} \\ \text{The nth term of an arithmetic progression is} \\ a(n)\text{ = a + (n - 1) x d} \\ \text{where a = first term, n = no of terms, and d = common difference} \\ a(n)\text{ = 80 + (n - 1) x 60} \\ \text{open the parenthesis} \\ a(n)\text{ = 80 + 60n - 60} \\ a(n)\text{ = 60n + 80 - 60} \\ a(n)\text{ = 60n + 20} \\  \\ \text{ Find the 100th term} \\ \text{let n = 100} \\ a(100)\text{ = 60(100) + 20} \\ a(100)\text{ = 6000 +2}0 \\ a(100)\text{ = 6020} \end{gathered}

7 0
1 year ago
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