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Leto [7]
3 years ago
10

the two cycles have center G where radius GI= 4ft, radius MG =6.5ft and MGC=72. Determine the total cost be to paint area MCAI i

f the quoted price is $40 per square foot? leave your answer in terms of pie until calculating the cost and then round to the nearest dollar
Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0
I have no clue what the answer would be, I’ve worked on it for 25 minutes, I will get back to you if I figure it out :,)
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SOMEONE PLEASE HELP I will give you brainliest it’s due in 11:59 pm TODAY!! Please
Snezhnost [94]
Shorter side: 130ft
longer side: 260ft
greatest possible area: 33800ft^2

basically get the equations for area and perimeter which will be

A: lw (length x width)
P: l + 2w

Substitute them into eachother and you get the equation:
-2w^2+520w = A

find the vertex of this parabola which will give you the greatest width which is 130m
Then u can find length and area from this width
4 0
2 years ago
Read 2 more answers
Answer all the questions
Verizon [17]
20. x > 15
19. x \leq -8
21. x \geq 42
5 0
3 years ago
A light bulb consumes 2400 watt-hours per day. How long does it take to consume 13800 watt-hours?
olga55 [171]
It will take about 5.75 days. basicly 5 days and 18 hours.
divide hours by total, and then find out 75 percent of 24
4 0
3 years ago
Read 2 more answers
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
At a local store, kelly and martin bought some notebooks and pencils. Kelly bought 4 notebooks and 25 pencils for 16.71. Martin
Nat2105 [25]
Let n = cost of 1 notebook
Let p = cost of 1 pencil

Then,

3n + 4p = 8.5
5n + 8p = 14.5

You can solve for one variable in terms of the other and then substitute into the remaining equation.

3n + 4p = 8.5
+ 5n + 8p = 14.5

Multiply the top equation by -2 so that the p-containing terms cancel each other out:

-2(3n + 4p = 8.5)
+ 5n + 8p = 14.5
-n + 0 = -2.5

So after dividing both sides by -1, we see that n = $2.5. Plugging into the first equation gives p = $0.25.


3n + 4p = 8.5
5n + 8p = 14.5
6 0
3 years ago
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