The chances that NEITHER of these two selected people were born after the year 2000 is 0.36
<h3>How to determine the probability?</h3>
The given parameters are:
Year = 2000
Proportion of people born after 2000, p = 40%
Sample size = 2
The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:
P = (1- p)^2
Substitute the known values in the above equation
P = (1 - 40%)^2
Evaluate the exponent
P = 0.36
Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36
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Answer: 5.259621477e13
Step-by-step explanation: Hoped this helped!!!
Answer:
f(t) = 5×0.87^t
Step-by-step explanation:
The general form for an exponential function described in this fashion is ...
... f(t) = (starting value) × (1 + (percent change))^t
Here, the "percent change" is -13%, or -0.13.
Then the value (1 + percent change) is (1 + (-0.13)) = 0.87. Putting this and the starting value into the form above, we have ...
... f(t) = 5 × 0.87^t
The answer is the first one.
Explanation:
X^3 stays the same because there are no other cubed numbers in the problem
Next you combine the x^2s
The x^2s are +3x^2 and +2x^2
Since they are both positive, you add them: 3x^2 + 2x^2 = 5x^2
Next you do the x values
-x and +6x, also known as 6x - x = 5x
Lastly, you just add in the -2 and get:
X^3 + 5x^2 + 5x - 2
Answer:
2,500
Step-by-step explanation:
Multiply 10,000 with 1/4 and since 1/4 equals to 25%.
10,000 x 1/4 = 2,500
Your answer is there and I hope this helps!
