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enyata [817]
3 years ago
15

The train station clock runs too fast and gains 7 minutes every 4 days. How many seconds will it have gained at the end of 10 da

ys?
Mathematics
1 answer:
lozanna [386]3 years ago
3 0
7 minutes every 4 days
7/4min every day
times 10
70/4min total
times 60 because 60 secods per minute
4200/4=seconds=1050 seconds



gains 1050 seconds
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1/4 - 3/5 write your answer is simplest form
blsea [12.9K]
First, you put each fraction into its greatest common denominator:
5/20 - 12/20. This then gives you the answer - 7/20.
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3 years ago
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When doctors prescribe medicine, they must consider how the drug’s effectiveness declines as time passes. If each hour a drug is
Dima020 [189]

Answer:

<u>The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes </u>

Step-by-step explanation:

Initial dose = 500 mg

Let's calculate the effectiveness of the drug hour by hour, this way:

After 1 hour: 90% of 500 = 450 mg

After 2 hours: 90% of 450 = 405 mg

After 3 hours: 90% of 405 = 364.5 mg

After 4 hours: 90% of 364.5 = 328.05 mg

After 5 hours: 90% of 328.05 = 295.25 mg

After 6 hours: 90% of 295.25 = 265.73 mg

After 7 hours: 90% of 265.73 = 239.16 mg

After 8 hours: 90% of 239.16 = 215.24 mg

After 9 hours: 90% of 215.24 = 193.72 mg

After 10 hours: 90% of 193.72 = 174.35 mg

After 11 hours: 90% of 174.35 = 156.92 mg

After 12 hours: 90% of 156.92 = 141.23 mg

Difference between 11 and 12 hours: 156.92 - 141.23 = 15.7 mg

Difference per minute between 11 and 12 hours: 15.7/60 = 0.262 mg

Time to reach a level of 150 mg in minutes after 11 hours = (156.92-150)/0.262

Time to reach a level of 150 mg in minutes after 11 hours = 26.4

<u>The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes </u>

4 0
3 years ago
Find the area of 6,4,15 help please
ra1l [238]

Answer:

Ps. don't  show your link next time becuase if you look up sequin you get TEXAS. answer is 360

Step-by-step explanation:

multiply one at a time

4 0
2 years ago
paid after the grace period, on average, more than 4 times in 2018, what are the null and alternative hypotheses? Select the cor
Mila [183]

Answer:

<em>H</em>₀: <em>μ</em> = 4 vs. <em>H ₐ</em>: <em>μ </em>> 4

Step-by-step explanation:

A null hypothesis is a sort of hypothesis used in statistics that intends that no statistical significance exists in a set of given observations.  

It is a hypothesis of no difference.

It is typically the hypothesis a scientist or experimenter will attempt to refute or discard. It is denoted by H₀.

Whereas, the alternate hypothesis is the contradicting statement to the null hypothesis.

The alternate hypothesis describes direction of the hypothesis test, i.e. if the test is left tailed, right tailed or two tailed.

It is also known as the research hypothesis and is denoted by H ₐ.

In this case we need to test whether the amount is paid after the grace period, on average, more than 4 times in 2018.

The hypothesis can be defined as follows:

<em>H</em>₀: <em>μ</em> = 4 vs. <em>H ₐ</em>: <em>μ </em>> 4

4 0
3 years ago
Which statement is true about the product square root of 2(3square root of 2 + square root of 14)?
sukhopar [10]

Answer:

\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}

Step-by-step explanation:

Given : \sqrt{2} (3\sqrt{2} +\sqrt{14})

Solution:

\sqrt{2} (3\sqrt{2} +\sqrt{14})

3*2+\sqrt{28})

6+2\sqrt{7}

Thus ,  \sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}

Thus the solution is irrational since square root 7 does not have a perfect square and equal to 6+2square root of 14

3 0
3 years ago
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