Answer:
Since b^2 -4ac = 256 we have 2 real distinct root roots
Step-by-step explanation:
4x^2+12x=7
We need to subtract 7 to get it in the proper form
4x^2+12x-7=7-7
4x^2+12x-7=0
The discriminant is b^2 -4ac
when the equation is ax^2 +bx+c
so a =4 b=12 and c=-7
(12)^2 - 4(4)(-7)
144 +112
256
If b^2 -4ac > 0 we have 2 real distinct roots
If b^2 -4ac = 0 we have one real root
If b^2 -4ac < 0 we have two complex root
Since b^2 -4ac = 256 we have 2 real distinct root roots
Answer: The answer is -1
Step-by-step explanation:
-4(y - 2) = 12
-4y + 8 = 12
- 8 - 8
_____________
-4y = 4
________
-4 -4
y = -1
30 students only 8 students own only a cat.
all even numbers
hope it really helps...!!!
