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polet [3.4K]
2 years ago
15

Tell whether the ratios form a proportionTrue orFalse ​

Mathematics
1 answer:
12345 [234]2 years ago
8 0

Answer:

True

Step-by-step explanation:

Hopefully this helps

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Given f(x) = 2* and g(x) = 2x + 1 evaluate (f?g)(o) and (g?f)(2).
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F(x)•g(x)=
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f(x)•g(x)=
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If you on a motorcycle trip of 30 miles in the and 5\19 of the trip is downhill, how many miles of the trip are not downhill? Re
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1/4 of the trip is not down hill                                        

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If sin 0=7/25, use the Pythagorean identity to find cos 0
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If a tennis ball has a diameter of 14, What is the volume of the tennis ball? Round to the nearest hundreth Use
vladimir2022 [97]

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\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7 \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (7)^3}{3}\implies V=\cfrac{1372\pi }{3} \\\\\\ \stackrel{using~\pi =3.14}{V\approx 1436.03} \end{array}

3 0
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Read 2 more answers
. The manager of a local small bank wants to estimate the average daily balance of all the checking accounts. Assume a random sa
MaRussiya [10]

Answer:

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

Step-by-step explanation:

Consider the provided information.

A random sample of 21 checking accounts at the bank are chosen,

That means n=21

df = n-1

df = 21-1=20

We need to  Construct and interpret a 95% confidence interval.

Determine t critical value for 95% confidence interval.

0.95=1-α

α=0.05

The sample size is small and it is a two tailed test.

From the t value table confidence interval is 2.086

An average daily balance is $303 and a standard deviation of $63.

CI=\bar x\pm t_c \times \frac{s}{\sqrt{n}}

Substitute the respective values.

CI=303\pm 2.086 \times \frac{63}{\sqrt{21}}

CI=303\pm 28.68

CI=274.32\ or\ 331.68

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

3 0
3 years ago
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