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USPshnik [31]
3 years ago
10

Can anyone help me with these two questions?

Mathematics
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

if I can read it I will can you repost the pic so we can see

Vaselesa [24]3 years ago
3 0

Answer:

14. ½ atan(x/5) − 5x / (50 + 2x²)

15. 12 asin(x/6) + x/3 √(36 − x²)

Step-by-step explanation:

14. x = 5 tan θ

θ/2 − sin(2θ)/4

Use double angle formula:

sin(2θ) = 2 tan θ / (1 + tan² θ)

tan θ = x / 5, so:

sin(2θ) = (2x/5) / (1 + x²/25)

sin(2θ) = 10x / (25 + x²)

Substitute:

θ/2 − (10x / (25 + x²)) / 4

θ/2 − 5x / (50 + 2x²)

½ atan(x/5) − 5x / (50 + 2x²)

15. x = 6 sin θ

12θ + 6 sin 2θ

Use double angle formula:

sin(2θ) = 2 sin θ cos θ

sin(2θ) = 2 sin θ √(1 − sin² θ)

sin θ = x / 6, so:

sin(2θ) = (x/3) √(1 − x²/36)

sin(2θ) = x/18 √(36 − x²)

Substitute:

12θ + 6 (x/18 √(36 − x²))

12θ + x/3 √(36 − x²)

12 asin(x/6) + x/3 √(36 − x²)

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bagirrra123 [75]

Using the relation between velocity, distance and time, it is found that:

  • The rate of the plane is of 840 km/h.
  • The rate of the wind is of 210 km/h.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time</u>, that is:

v = \frac{d}[t}

Flying against the wind, an airplane travels 2520 kilometers in 4 hours, that is:

v - v_w = \frac{2520}{4}

v - v_w = 630

v = 630 + v_w

Flying with the wind, the same plane travels 9450 kilometers in 9 hours, hence:

v + v_w = \frac{9450}{9}

v + v_w = 1050

v = 1050 - v_w

Hence, solving for the wind's speed:

630 + v_w = 1050 - v_w

2v_w = 420

v_w = \frac{420}{2}

v_w = 210

For the plane, we have that:

v = 1050 - 210 = 840.

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

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