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anzhelika [568]
3 years ago
5

I need help... i need the answer

Mathematics
2 answers:
just olya [345]3 years ago
7 0
Um idk how to help it is basically already done
Katena32 [7]3 years ago
3 0
The answer is basically already solved in the picture
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Danielle's text messaging plan costs $14 for the first 500 messages and 10¢ for each additional text message. If she owes $27.70
sasho [114]

27.7-14=Cost above 500 msg

13.7=C

E=number of Extra messages sent

C=0.1E

13.7/0.1=E

137=E

Total messages=T

T=500+E

T=500+137

T=637

Danielle sent 637 messages in September

4 0
3 years ago
Ellen drove 357.3 miles.for each gallon of gas,the car can travel 21 miles.select a reasonable estimate of the number of gallons
kari74 [83]
Just a little over 17 gallons was used
7 0
3 years ago
lipka reads a book of 1/34 hrs everyday she reads the entire book in 6 days how many hours in all were required by her to read t
marshall27 [118]

Answer: She needs 10 1/2 hours to read the book.

Step-by-step explanation:I day = 1 3/4 hours

6 days = 1 3/4 x 6

6 days = 7/4 x 6

6 days = 42/4

6 days = 10 1/2 hours

8 0
2 years ago
In the town of sleepy Oak. the fine for speeding ticket is $32.65 + s dollars. Where s is the miles per hour over the speed limi
Mkey [24]
A:  38.4 - 25 = 13.4
      13.4 + 32.65 = $46.05

B:  50.15 - 32.65 =  17.5
         17.5 + 25 =  42.5 mph
5 0
3 years ago
What system shows the correct numbers to multiply by the coefficients in order to eliminate y from the first two
Ann [662]

Answer:

3 (5x+2y = 0)

2 (2x – 3y = -19)

Step-by-step explanation:

5x+2y=0 (1)

2x-3y=-19 (2)

To eliminate y from the first two equation when applying the linear combination method

We will multiply y Equation (1) and (2) with 3 and 2 respectively so that the coefficients of y in the two equations +6 and -6 respectively

3(5x+2y=0)

2(2x-3y=-19)

We have,

15x+6y=0 (3)

4x-6y= -38 (4)

Add Equation (3) and (4)

19x=-38

x= -2

Substitute x= -2 into (1)

5x+2y=0

5(-2)+2y=0

-10+2y=0

-10= -2y

y=-10/-2

=5

y=5, x=-2

3 0
3 years ago
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