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snow_lady [41]
3 years ago
13

Jessamine wants to ride her bike at least 85 miles per week. She rides to and from school 5 days per week. Her house is 6.25 mil

es from her school. She rides an additional 2.5 miles for each trip, t, she makes around the park. Which inequality represents the situation?
5 (2) (6.25) + 2.5 t less-than-or-equal-to 85
5 (2) (6.25) + 2.5 t less-than 85
5 (2) (6.25) + 2.5 t greater-than-or-equal-to 85
5 (2) (6.25) + 2.5 t greater-than 85
Mathematics
2 answers:
katrin [286]3 years ago
7 0

Answer:

the answer would be 5 (2) (6.25) + 2.5 t greater than or equal to 85

Step-by-step explanation:

Jessamine wants to ride at least 85 miles a week, so we can cross out the top 2. the 4th option is saying great than 85, but she wants to go 85 miles or greater.

aalyn [17]3 years ago
4 0

Step-by-step explanation:

Let's translate the verbal language to algebraic language.

She rides to and from school 5 days per week, 6.25 miles each route => 5*2*6.25 miles = 62.5 miles.

She rides additioanly around the park 2.5 miles for each trip t => 2.5*t = 2.5t

Total miles of her rides per week: 62.5 miles + 2.5t

She wants to ride minimum 85 miles => 62.5 + 2.5t ≥ 85

Then, the situation is represented by this inequality:

2.5t + 62.5 ≥ 85

You can develop it and get to several equivalent inequalities, for example:

2.5t ≥ 85 - 62.5

2.5t ≥ 22.5

t ≥ 9

Any of the four forms are equivalent and a valid answer.

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What is the solution for the equation -15=5(3y-10)-5y
marissa [1.9K]

Answer:

  • \Large\boxed{\sf{y=\dfrac{7}{2} }}

Step-by-step explanation:

Isolate the variable of y from one side of the equation.

-14=5(3y-10)-5y

<u>First, switch sides.</u>

\sf{5\left(3y-10\right)-5y=-15}

Use the distributive property.

<u>DISTRIBUTIVE PROPERTY:</u>

A(B-C)=AB-AC

5(3y-10)

Multiply by expand.

5*3y=15y

5*10=50

15y-50-5y

15y-5=10y

= 10y-50

10y-50=-15

Add by 50 from both sides.

10y-50+50=-15+50

Solve.

10y=35

Then, you divide by 10 from both sides.

10y/10=35/10

Solve.

Divide the numbers from left to right.

35/10=7/2

y=7/2

Divide is another option.

7/2=3.5

\Longrightarrow: \boxed{\sf{y=\dfrac{7}{2}}}

  • <u>Therefore, the correct answer is y=7/2.</u>

I hope this helps. Let me know if you have any questions.

7 0
1 year ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

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Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

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c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

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Answer:

50 in ^3

Step-by-step explanation:

V = 1/3 pi r^2 h

We know that pi = 3  

the diameter is 5 so the radius is 1/2 the diameter of 5/2 = 2.5

The height is 8

V = 1/3 ( 3) ( 2.5)^2 ( 8)

V = 50 in ^3

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Answer: 1.6km

Step-by-step explanation: 2.8km - 1.2km

The student is still north from school.

I hope this answer helped! :)

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