I learned this a while ago and totally forgot how to do it. Really need help.
1 answer:
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Answer:
The Area of Rectangular Garden is 1044 feet²
Step-by-step explanation:
According to question
The perimeter of the garden = 82 ft
Let the length be L ft
The width be W ft
Now as per question
L = 5 + ( 2× W )
∵ Perimeter of Rectangle = 2 × ( Length + Width )
Or , Perimeter of Rectangle = 2 × ( L+ W )
Or, 82 = 2 × ( L+ W )
Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]
Or, 82 = 2 × ( 5 +3W )
Or, 41 = 5 + 3W
Or, 41 - 5 = 3W
So, 3W= 36
∴ W = = 12 feet
I.e Width = 12 feet
And L = 5 + ( 2× W )
Or, Length = 5 + 24 = 29 feet
Now The Area of Rectangle = Length × width
So, The Area of Rectangle = 29 ft × 36 ft
The Area of Rectangle is 1044 feet²
Hence The Area of Rectangular Garden is 1044 feet² Answer
Step-by-step explanation:
using formula that cos= b/h
