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Stels [109]
3 years ago
9

what is the equation, in slope-intercept from, of the line that is perpendicular to the line y - 4 = -2/3 (x -6 ) and passes thr

ough the point (-2,-2)?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0

Turn y - 4 = -2/3(x - 6) into a linear equation.

y - 4 = -2/3(x - 6)

y - 4 = -2/3x + 4

 +4                +4

y = -2/3x + 8

The equation that is perpendicular to y = -2/3x + 8 is y = 3x + 4 as shown in the image below using a graph.


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If m1=35° and m2=75°, what is m3?​
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the total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib. if the weight of the bag of sugar is 1.4 Ib, what is the we
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0.4 lbs each.

<h3>Further explanation</h3>

<u>Given: </u>

  • The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
  • The weight of the bag of sugar is 1.4 Ib

<u>Question: </u>

What is the weight of each piece of butter?

<u>The Process: </u>

The two steps for obtaining the weight of each piece of butter are as follows:

<u>Step-1:</u> the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }

<u>Step-2:</u> the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }

Let's also consider the following quick steps.

<u>Quick steps: </u>

\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }

Therefore, the weight of each piece of butter is 0.4 lbs.

<h3>Learn more </h3>
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Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

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Step-by-step explanation:

From the attached image, we can see that ∠1 and ∠2 form a pair of alternate exterior angles. Thus; ∠1 = ∠2.

Now since they are congruent, it means that their lines will be parallel.

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