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Jet001 [13]
4 years ago
9

Find the recursive formula for 18, 15, 12, 9, . .

Mathematics
1 answer:
Lady bird [3.3K]4 years ago
5 0

Answer: a_{n}=a_{n-1}-3  ,  n\geq 2

Step-by-step explanation:

a_{1} = 18

The common difference = -3

Therefore :

a_{n}=a_{n-1}-3  ,  n\geq 2

check:

when n = 2

a_{2}= a_{1}-3

a_{2}=18-3 = 15

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For this case we have the following system of equations:

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Equating the equations we have:

x ^ 2-x = x + 3\\x ^ 2-x-x-3 = 0\\x ^ 2-2x-3 = 0

To find the solutions we factor the equation. To do this, we look for two numbers that, when multiplied, result in -3 and when added, result in -2.

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Thus, the solutions are:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

ANswer:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

3 0
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