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3 years ago

Find the greatest common factor of 18, 36,18,36,18, comma, 36, comma and 454545.

Mathematics

2 answers:

lilavasa [31]3 years ago

6 0

Dkkfjfjfkfkdfjjddjfjfdfjfjdjfjff

Rama09 [41]3 years ago

5 0

The gfc of 18, 36, 18, 36, 18, 36, 45, if that’s what you’re asking for, is 9
answer: 9

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Need help on this loviesss

aev [14]

Step-by-step explanation:

perimeter of triangle = s + s + s

perimeter of given triangle = 22 + 17 + 14

= 53 cm

therefore, perimeter of given triangle is <em>53 cm</em>

7 0

3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

The blue segment below is a diameter of O. What is the length of the radius of the circle?

svlad2 [7]

Diameter= 2 times the radius

2r=d
2r=10.2
R= 10.2/2
R=5.1

Therefore, the radius is 5.1 units which makes the answer choice C correct.

Hopefully, this helps!

5 0

2 years ago

Read 2 more answers

What is 1.3742 rounded to the nearest tenth?

REY [17]

Answer:

1.4 that is the true answer

Step-by-step explanation:

go to the place right after the decimal and then look at the number next to it.if it is greater the 5 it goes up to 1.4 and it is

6 0

2 years ago

How can you write -1/4x-9 on a graph

Dmitrij [34]

Answer:

Slope : -1/4

y-intercept : -9

x... 0 , 1

y... -9 , -37/4

Step-by-step explanation: Graph the line using the slope and y-intercept, or two points. GRAPH IS DOWN BELOW!

Hope this helps you out.

4 0

3 years ago