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erma4kov [3.2K]
3 years ago
12

The fixed cost of making clothes for a clothing store for three years is $40,000. The number of pieces of clothing bought per ye

ar is variable and ranges between 100 and 200 pieces of clothing. Each garment is sold for $90. Look at the five scenarios where random numbers were generated to show the number of garments for three years. Scenario Year 1 Year 2 Year 3 A 134 194 127 B 143 109 141 C 170 194 104 D 171 164 122 E 141 160 173 In which of these simulated scenarios is your total income less than your total cost? A
Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0
Scenario B - 143 (Year 1), 109 (Year 2), 141 (Year 3)

In this scenario, the total income is 35,370. This is calculated by getting the sum of the number of garments in the span of three years and multiplying it by the rate of $90 per garment. Your income of 35,370 is lesser than your fixed cost for three years of 40,000.
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Step-by-step explanation:

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A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
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Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

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