All categories

1 year ago

PLEASE HELP VERY URGENT

Mathematics

1 answer:

worty [1.4K]1 year ago

3 0

Answer:

A. square root of a^2 + b^2 for both answers

Step-by-step explanation:

The first problem, we are given

a^2 + b^2 = c^2

What we do is solve for c.

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

For problem 2,

WE can apply the Pythagorean theorem because we have a right triangle.

The equations is

a^2 + b^2 = c^2 like the first problem

Solving gets us

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

You might be interested in

9. Sonya opened a savings account with and deposits each week. Brad opened a savings account with and contributes each week. Aft

Lapatulllka [165]

It will take 6 weeks for Brad to get twice the amount as Sonya.
Sonya will have $260 dollars and Brad will have $360

8 0

2 years ago

PLEASE HELP ME T-T I NEED IT’S SOLUTION

Vlada [557]

The area is 8_/3

hope it helps.

6 0

2 years ago

-15 + 8 = A) -23 B) -7 C) 11 D) 23

bagirrra123 [75]

Answer:

B) -7

Step-by-step explanation:

since since since there is more of the negative number then the positive number, the positive number gets canceled out.

6 0

3 years ago

Read 2 more answers

Solve for r. 0.5(r+2.75) = 3

nirvana33 [79]

Answer:

r=3.25

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train tra

stepan [7]

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor =?

Solution:

The speed of the train A = $\frac{Distance}{time}$

The speed of train A = $\frac{175}{4}$

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5 miles per hours

Train A travels faster

$Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}$

$rate = \frac{43.75}{43.5}$

rate =1.01

7 0

2 years ago