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Darina [25.2K]

2 years ago

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Mathematics

1 answer:

kvasek [131]2 years ago

5 0

Answer: $4\sqrt{5}x^7$

Step-by-step explanation:

$\sqrt{80}x^7$

$=\sqrt{2^4\cdot \:5}x^7$

$=\sqrt{2^4}\sqrt{5}x^7$

$=4\sqrt{5}x^7$

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Answer:

I believe the answer is 9

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Is subtraction of decimals associative? If not, give a counter example.

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Associative property is only applied to addition and multiplication. Thus, it can't be applied to subtraction. This property is manifested when you get the same answer no matter where you put the parenthesis. Example of associative property is:

(50 + 2) + (92 + 6) = 52+98 = 150
50 + (2+92) + 6 = 50 + 94 + 6 = 150

Here is the counter example for the subtraction of decimals:

(3.45 - 8.92) - (1.9 - 7.3) = -5.47 - ⁻5.4 = -0.07
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As you can see, the answers are not the same.

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Find the slope of the line that passes through (50, -70) and (77, 62). Simplify your answer and write it as a proper fraction, i

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Earth revolves around the Sun in 365 days, but the planet Mercury does so in only 88 days. Compared to Earth, how many more comp

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Answer:

In a 1000 days Mercury will make 8.624 more revolutions than Earth!

Step-by-step explanation:

Earth takes 365 days to make a complete revolution.

we can say that the rotational speed of Earth is $\dfrac{1}{365}\frac{\text{rev}}{\text{day}}$

so, in a 1000 days how many revolutions will Earth have made?

$\dfrac{1}{365}\frac{\text{rev}}{\text{day}}\times(1000\,\text{day})$

see that the 'day's cancel out. Simply multiply the two numbers!

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Next, do the same for Mercury

we can say that the rotational speed of Mercury is $\dfrac{1}{88}\frac{\text{rev}}{\text{day}}$

as it completes 1 revolution in 88 days.

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$\dfrac{1}{88}\frac{\text{rev}}{\text{day}}\times(1000\,\text{day})$

multiplying by 1/88 by 1000 yields:

$11.363\text{rev}$

The Question is how many MORE complete revolutions will Mercury make in 1000 days?

We need to subtract the revolutions of Mercury with Earth to find how far ahead is Mercury from Earth

$11.363\text{rev} - 2.739\text{rev}$

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