Answer: 
<u>Step-by-step explanation:</u>
Isolate w by performing the following steps
- Multiply by 6 on both sides to clear the denominator
- Subtract 3 from both sides
- Divide both sides by 2
![y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B1%7D%7B2%7D%2B%5Cdfrac%7Bw%7D%7B3%7D%5C%5C%5C%5C%5C%5C6%5Cbigg%5By%3D%5Cdfrac%7B1%7D%7B2%7D%2B%5Cdfrac%7Bw%7D%7B3%7D%5Cbigg%5D%5Cquad%20%5Cimplies%20%5Cquad%206y%3D3%2B2w%5C%5C%5C%5C%5C%5C6y-3%3D3-3%2B2w%5Cquad%20%5Cimplies%20%5Cquad%206y-3%3D2w%5C%5C%5C%5C%5C%5C%5Cdfrac%7B6y-3%7D%7B2%7D%3D%5Cdfrac%7B2w%7D%7B2%7D%5Cquad%20%5Cimplies%20%5Cquad%20%5Clarge%5Cboxed%7B%5Cdfrac%7B6y-3%7D%7B2%7D%3Dw%7D)
Answer:
Step-by-step explanation:
Hello
let's assume that we are looking for x >=0
Let's assume that we are looking for x>=0
so the correct answer is 5
56 is the answer so it's A, C and E.
Calm Down this is a nasty proof
CB is parallel to ED (Given)
CB is congruent to ED (Given)
Angle CBF is congruent to Angle EDF (Vertical Angles)
Angle DEF is congruent to Angle BCF (Alternate Interior Angles)
Angle EDF is congruent to Angle CBF (Alternate Interior Angles)
Therefore we now have enough information to solve. We have a side angle side triangle here so.....
Triangle CBF is congruent to Triangle EDF because of the Side Angle Side Theorem.
Good Luck and Your Welcome
Answer:
Step-by-step explanation: solution.. 8/10 of candy bar left over to be split into 1/3 pieces...
(8/10)÷1/3=12/5=2.4pieces
