Write an equation in standard form for a line that passes through (2,2) and (0,-3).
1 answer:
So,
The standard form is:
y = mx + b
First, we find "m," the slope. Subtract the y-coordinates from each other. Do likewise with the x-coordinates.
2 - -3 = 5
2 - 0 = 2
Slope = 5/2
![y= \frac{5}{2} x+b](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B5%7D%7B2%7D%20x%2Bb)
Now, we can substitute the second solution into this equation for x and y and solve for "b."
![-3= \frac{5}{2} *0+b](https://tex.z-dn.net/?f=-3%3D%20%5Cfrac%7B5%7D%7B2%7D%20%2A0%2Bb)
![-3= b](https://tex.z-dn.net/?f=-3%3D%20b)
Now we have our complete equation.
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