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Dennis_Churaev [7]
2 years ago
7

Write an equation in standard form for a line that passes through (2,2) and (0,-3).

Mathematics
1 answer:
asambeis [7]2 years ago
8 0
So,

The standard form is:
y = mx + b

First, we find "m," the slope.  Subtract the y-coordinates from each other.  Do likewise with the x-coordinates.

2 - -3 = 5
2 - 0 = 2

Slope = 5/2

y= \frac{5}{2} x+b

Now, we can substitute the second solution into this equation for x and y and solve for "b."

-3= \frac{5}{2} *0+b

-3= b

Now we have our complete equation.

y= \frac{5}{2} x-3
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Step-by-step explanation:

<u>Substitute x = -118 and y = -114 into the expressions:</u>

<u>1</u><u>:</u>

- 118 +  - 114 =  - 232

Correct.

<u>Use integer rule for #2:</u>

- 118 + 114 =  - 4

Incorrect.

*This answer can be a positive when terms are switched.

<u>3:</u>

- 118 \times  - 114 = 13452

When two negatives multiply, the product remains positive.

Incorrect.

<u>4:</u>

<u>\frac{ - 118}{ - 114}  = 1.035</u>

When two negatives divide, the quotient remains positive.

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Step-by-step explanation:

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Find an equation of the line that passes through (3,4) and parallel to 4x-2y=5
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4x - 4x - 2y = -4x + 5
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Step-by-step explanation:

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