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just olya [345]
3 years ago
6

Use words and drawings to show 95

Mathematics
1 answer:
lawyer [7]3 years ago
3 0
Ninety-five  xcv  noventa y cinco<span>  draw 9 tens and 5 ones
                
                    hope this helps    



</span>
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Need help on 6. 8th grade math
frutty [35]
Don't know about the TV problem, sorry.

For the next one (Dylan) = 14.1 inches
Use the Pythagorean Theorem a^2+b^2 = c^2
10^2 + 10^2 = c^2
100 + 100 = c^2
200 = c^2

Take the square root of both sides. The hypotenuse is equal to the square root of 200, which is 14.1 when rounded to the nearest tenth of an inch.

Hope this helps
6 0
3 years ago
What is the value of X given that the two triangles are similar.
grin007 [14]

Answer:

x = 13

Step-by-step explanation:

ΔRST≈ΔYSZ

therefore:

RT/ST = YZ/SZ

(3x-7)/40 = (2x+2)/35

cross-multiply:

40(2x+2) = 35(3x-7)

80x+80 = 105x-245

80 = 25x-245

325 = 25x

325/25 = x

x = 13

3 0
3 years ago
A worker in a silver mine descends 51 feet. Use an integer to represent the change in the​ worker's position.
Contact [7]

Answer:

-51

Step-by-step explanation:

because it is defending causing the integer to become a negative

6 0
4 years ago
Read 2 more answers
The function d(s) = 0.0056s squared + 0.14s models the stopping distance
victus00 [196]

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be d(s) = 0.0056\cdot s^{2} + 0.14\cdot s, where d is the stopping distance measured in metres and s is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of d(s).

2) Add the function d = 7\,m.

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

4 0
3 years ago
76763476-2345-345-324-23+5324+345234÷6847397475287365x3789127482297547 85345455345325234-345325+32453892727-25666634872962365823
Nadusha1986 [10]

Answer:

−1.43000372×10^{29}

Step-by-step explanation:

76763476-2345-345-324-23+5324+345234÷6847397475287365x3789127482297547 85345455345325234-345325+32453892727-2566663487296236582345x54287395 79238365379245÷97438528453492= what

76763476-2345-345-324-23+5324+(1.91041289x10^{22})-345325+32453892727-(1.43000391x10^{29})

76765763+(1.91041289x10^{22})-345325+32453892727-(1.43000391x10^{29})

−1.43000372×10^{29}

4 0
3 years ago
Read 2 more answers
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