Complete question:
A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability
distribution below?
Grade(X)_____ 1_____2_____3_____4_____5
Frequency____3 _____5____ 9 ____ 5 ____ 3
P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1
Answer:
3
Step-by-step explanation:
Given the probability distribution :
Grade(X)_____ 1_____2_____3_____4_____5
Frequency____3 _____5____ 9 ____ 5 ____ 3
P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1
The mean of the distribution :
Σ(X * P(X)) :
(1*0. 1) + (2 * 0.2) + (3 * 0.4) + (4 * 0.2) + (5 * 0.1)
0.1 + 0.4 + 1.2 + 0.8 + 0.5
= 3
What point represent point p after a 90degree counter clockwise turn from the origin.
To solve, draw a line from the origin to point p. Draw a line from the origin that is perpendicular to line OP (origin to p). Make sure the line is in the counterclockwise direction, This will leave you at point ___
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Go down if you still don't understand\/
Point A
If we are given a triangle JKL and we assume that this is a right triangle, we can find the measure of the angle LJK by using formulas derived from the Pythagorean Theorem.If opposite side = 10 hypotenuse = 15then, we can use: cos (x) = opposite / hypotenusesin (x) = 10 / 15
Step-by-step explanation:
area of first triangle =1/2×112×202×sin30°
area of second circle=1/2×202×197×sin60.5°
- 1/2×202×197×0.870
- 17310.39m²
Total area of estates=area of first triangle +area of second triangle
hope it helps.
Answer:
The measure of the arc DAC is 240°
Step-by-step explanation:
we know that
The semi-inscribed angle is half that of the arc it comprises.
so
m∠RDC=(1/2)[arc DAC]
we have
m∠RDC=120°
substitute
120°=(1/2)[arc DAC]
240°=[arc DAC]
Rewrite
arc DAC=240°
