Sqrt(486) - sqrt(24) + sqrt(6)
find the factors of 486 that we can remove from under the square root sign
2 * 243
2 * 3 * 81
2 * 3 * 9 * 9 (we have 2 nines, we can move a 9 outside the sqrt sign)
sqrt(486) = 9 sqrt(6)
Repeating for sqrt(24)
2 * 12
2 * 2 * 6
2 * 2 * 2 * 3 (we can move a 2 outside the sqrt
sqrt(24) = 2 sqrt(6)
Finally, add all 3 terms together
9 sqrt(6) - 2 sqrt(6) + sqrt(6)
8 sqrt(6)
8 times square root of 6 is the final answer
It is a part of slope form ( intercept
Answer:
x= 2
x= -3
Step-by-step explanation:
<u>Solving as normal quadratic equation:</u>
- 2x^2+2x=12
- x^2 +x = 6
- x^2 + x - 6= 0
- x = (-1 ± √(1+4*1*6)/2
- x = ( - 1 ± √25)/2
- x = (-1 ± 5)/2
- x= 2
- x= -3
<u>Roots are</u> 2 and -3
Complentary angles add to 90 degrees
a and b are complentary
a+b=90
a=7x+4
b=4x+9
so
7x+4+4x+9=90
combine like terms
11x+13=90
minus 13 both sides
11x=77
divide both sides by 11
x=7
m a =7x+4=7(7)+4=49+4=53
m b=4x+9=4(7)+9=28+9=37
angle a measures 53 degrees
angle b measures 37 degrees
Y-___enter y-coordinate of the point here= -3(x-__enter the x-coordinate here)
