Answer:
Using the equation only w is the independent variable and t is the dependent variable. The meaning behind each variable in the context could change this.
Step-by-step explanation:
On a graph called the coordinate plane, there are two axis. The horizontal axis is the x-axis and is known as the independent variable. A great example of an independent variable is time. Time is always represented on the x-axis because time passes by. It does not depend on anything. If t is time in t = 20w then it is independent and not dependent.
The other axis is the y-axis. It is the vertical axis on the graph. It is called the dependent variable because its value depends on x. For example, if you were looking at miles per hour, the number of miles would depend on how many hours you traveled. You have to know the time to find miles. This is a dependent variable.
Answer:
GJK
Step-by-step explanation:
An inscribed angle is an angle formed by two line segments in a circle that intersect on the circle. The line segments must touch the circle at two points The angle must be on the circle itself.
GIH is not inscribed because I is in the center of the circle not on the circle
GJK is an inscribed angle GJ and JK touch the circle at two point and are inside the circle.
IGJ IG does not touch the circle at two points
JKL KL is outside the circle
Answer:
7x + 32 and 123
Step-by-step explanation:
One way to divide is to use the divisor as a factor in the numerator
Consider the numerator
7x(x - 4) + 28x + 4x - 5
= 7x(x - 4) + 32(x - 4) + 128 - 5
= 7x(x - 4) + 32(x - 4) + 123
quotient = 7x + 32 and remainder = 123
= x + 32 + 
Answer:
T = 3
Step-by-step explanation:
To find the period, find the distance it takes to complete one cycle.
Answer:
Area segment = 3/2 π - (9/4)√3 units²
Step-by-step explanation:
∵ The hexagon is regular, then it is formed by 6 equilateral Δ
∵ Area segment = area sector - area Δ
∵ Area sector = (Ф/360) × πr²
∵ Ф = 60° ⇒ central angle of the sector
∵ r = 3
∴ Area sector = (60/360) × (3)² × π = 3/2 π
∵ Area equilateral Δ = 1/4 s²√3
∵ The length of the side of the Δ = 3
∴ Area Δ = 1/4 × (3)² √3 = (9/4)√3
∴ Area segment = 3/2 π - (9/4)√3 units²
