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2 years ago

Simplify the expression 6 (-3b + 1)

Mathematics

1 answer:

finlep [7]2 years ago

7 0

Answer:

−18b+6

Step-by-step explanation:

6(−3b+1)

Use the distributive property to multiply 6 by −3b+1.

−18b+6

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State the range of the relation

Finger [1]

The range of the given relation is D. R = {-1, 3, 5, 8}.

Step-by-step explanation:

Step 1:

The range of a relation is the second set of values while the domain constitutes the first set of values.

There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.

Step 2:

The range of (1, -1) = -1,

The range of (2, 3) = 3,

The range of (3, 5) = 5,

The range of (4, 8) = 8.

Combining these values we get the range as {-1, 3, 5, 8} which is option D.

3 0

3 years ago

Do you think a polynomial can be a factor of another polynomial?

Vladimir [108]

Answer:

Yes

Step-by-step explanation:

Example

x+2 is a factor of 2x+4.

2(x+2) = 2x+4.

6 0

2 years ago

Of the 120 apartments in a building, 75 have been scheduled to receive new carpet. What fraction of the apartments have not been

Ilia_Sergeevich [38]

Hello!

To find the fraction of the apartments that have not been scheduled to receive new carpet, we need first need find the number of apartments not receiving new carpet, by subtracting the total amount of apartments, by the 75 that have been scheduled.

120 - 75 = 45 apartments

Next, we need to create a fraction. Since 45 out of 120 apartments not are scheduled to get new carpeting, the fraction of these values is 45/120. This can be reduced to 3/8.

Therefore, your final answer is 45/120, simplified to 3/8.

6 0

3 years ago

Read 2 more answers

How to solve this problem?

Ganezh [65]

The answer should be 1y and -6y

3 0

3 years ago

drag the gray arrow so that it is pointing midway between horizontal and vertical, heading downward and toward the right. extend

alex41 [277]

The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.

These are due to the Doppler effect, the equation of frequency detected by the observer as

$f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } }$ where $\beta = \frac{v}{c}$ , v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.

Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

To learn more about frequency click here brainly.com/question/26177128

#SPJ4

7 0

8 months ago