I^3 = i^(2+1) = i^2 x i -1 x i = -i
Answer:
x=35
Step-by-step explanation:
3x+3=108
3x=108-3
3x= 105
x= 105/3
x=35
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X^2 + 9y^2 = 25
x^2/5^2 + (3y)^2/5^2 = 1
This represent an equation of an ellipse with cente at the origin, the horizontal major axis running from -5 to 5 and vertical minor axis running from -5/3 to 5/3
The third graph is the correct answer.
