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vagabundo [1.1K]
3 years ago
15

2times 5 to the power of 2

Mathematics
1 answer:
Bumek [7]3 years ago
3 0
You do 2(5)^2 and the answer is 50

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The product of a number w and 737
aivan3 [116]
Given that the number is w ...so the product of w and 737 would be w × 737...=>737w.... Hope it helps!!!
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3 years ago
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BaLLatris [955]

If There is a math equation you can use math-way.

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3 years ago
Read 2 more answers
Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.
sweet-ann [11.9K]

Answer:

x = 10\sqrt{3}, y = 10

Step-by-step explanation:

Using the sine/ cosine ratios in the right triangle and the exact values

sin60° = \frac{\sqrt{3} }{2} , cos60° = \frac{1}{2} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{x}{20} = \frac{\sqrt{3} }{2} ( cross- multiply )

2x = 20\sqrt{3} ( divide both sides by 2 )

x = 10\sqrt{3}

and

cos60° = \frac{adjacent}{hypotenuse} = \frac{y}{20} = \frac{1}{2} ( cross- multiply )

2y = 20 ( divide both sides by 2 )

y = 10

4 0
2 years ago
if a coin is tossed 4 times, the odds of it coming up either heads every time or tails every time are 1:7.What is the probabilit
ivanzaharov [21]

Answer:

1

Explanation:

From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses

What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin

For four throws, it means all four are heads or all four are tails

If all four are heads, we have the probability of this happening as:

\text{ (}\frac{1}{8})^{}

if all four are tails, we have the probability as:

\frac{7}{8}

Now, the probability of either heads or all tails after 4 tosses will be:

\text{ }\frac{1}{8}\text{ + }\frac{7}{8}\text{ = 1}

8 0
1 year ago
Here is a growing pattern of squares:
Flura [38]

Answer:

squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1

Step-by-step explanation:

3 0
2 years ago
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