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vagabundo [1.1K]
3 years ago
15

2times 5 to the power of 2

Mathematics
1 answer:
Bumek [7]3 years ago
3 0
You do 2(5)^2 and the answer is 50

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Points C and D are equidistant from point A. Complete the following table to prove that AEC≅ AED
inna [77]
To prove that <span>AEC≅ AED, we need to write following proofs or statement reasons.

It is given that points C and D are equidistant to point A. Hence,
</span><span>AD ≅ AC

Next, </span><span>CAE ≅ DAE. AE is the common side or the included side. 
</span><span>
Then, </span><span>AE ≅ EA by Reflexive Property of Congruence as it is congruent to itself.

Lastly, </span><span>EAD ≅ EAC by Symmetric Property of Congruence as these triangles are mirror image of each other.
</span>
Therefore, we can conclude that AEC≅ AED by SSS or Side-Side-Side. That is when all sides of triangles are congruent then both triangles are deemed to be equal.

3 0
2 years ago
Read 2 more answers
Is Figure B a scale copy of Figure A?
kari74 [83]

Answer:

No.

Step-by-step explanation:

The ratio of the lengths of the vertical sides from A to B is 2/4 which equals 1/2.

The ratio of the lengths of the horizontal sides of A to B is 4/11.

Since 4/11 is not equal to 1/2, figure B is not a scale copy of figure A.

5 0
1 year ago
What is the circumference of a circle with a diameter of 72 feet? Leave your answer in
Anettt [7]

Answer:

72π feet

Step-by-step explanation:

circumference of circle= 2πr

Diameter= 2(radius)

radius of circle

= 72 ÷2

= 36 ft

Circumference

= 2(π)(36)

= 72π ft

4 0
2 years ago
What sample size is needed to give a margin of error within plus-or-minus 5% in estimating a population proportion with 90% conf
VARVARA [1.3K]

Answer: 271.

Step-by-step explanation:

When the prior population proportion of success is not available, then the formula to find the sample size is given by :-

n=00.25(\dfrac{z_{\alpha/2}}{E})^2

Given : Significance level : \alpha: 1-0.90=0.1

By using the standard normal distribution table ,

Critical value : z_{\alpha/2}=1.645

Margin of error : E=0.05

Then , the required minimum sample size will be :-

n=0.25(\dfrac{(1.645)}{0.05})^2=270.6025\approx271

Hence, the required minimum sample size is 271.

4 0
2 years ago
Help please 9 and 10
DIA [1.3K]
9 is obtuse isosceles 10 is scalene,right  <span />
7 0
2 years ago
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