Math help please.. number 13
1 answer:
Use the Law of Cosines here with angle A as your reference angle. It will be the one that the helicopter is at, the one we are looking for. If that angle is angle A, then the side across from it is a, measure of 11.4. Here's how the Law looks in our particular situation: 
. Simplifying a bit we get 129.96 = 54.76 + 72.25 - 125.8cos(A) Combining like terms across the equals sign gives us 2.95 = -125.8 cosA. Doing the division we get -.0234499205 = cosA. Find the angle using the 2nd and cos buttons on your calculator. It's 91.34°, rounded to just 91°. Choice A
You might be interested in
A passenger flies on a heading of N40W with an airspeed of 240 km/h. His actual ground velocity is 250 km/h at a bearing of N60E. the speed and direction of the wind are V=245.15kw/h at N83.46E. This is further explained below.
<h3>What is the speed and direction of the wind.?</h3>Generally, the equation for the cosine rule is mathematically given as
a2 = b2 + c2 – 2bc cos ∠x.
Therefore
V^2 = (240^2 + 250^2) – (2(240*250)* cos 100)
V^2=140937.7813
V=375.42kw/h
In conclusion, the sine rule is mathematically given as
Sin x/240=sin60/375.42kw/h
Therefore
sin x=sin100*250/375.42kw/h
x=40.981
Hence
Direction N83.46E
Read more about Speed
#SPJ1