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Hatshy [7]
3 years ago
11

Complete the formula to find the area of the triangle plz help I have only 15 mins left​

Mathematics
2 answers:
scoray [572]3 years ago
6 0
1/2*3*4=6



Explanation:

The height is 3 cm and the base is 4cm.

I believe 5 is there to trick you. The bottom Is always the base and the straight line going vertically is always the height.


1/2*3*4=6
Vinvika [58]3 years ago
6 0

Answer:

6 cm²

Step-by-step explanation:

\frac{1}{2} × 4 cm × 3 cm = 6 cm²

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Does the equation 14 - 3x = -4x have one, many or no solution?​
BabaBlast [244]

Answer:

one solution,x=- 14

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
F(x)=9÷4x-15 for x=4
enyata [817]

9/4x  -15     for x=4

To find this answer you must plug the 4 everywhere the x is located.

(9/4)(4)  -15

Multiply 9/4 by 4

(9/4) x 4 = 9

Now we take our 9 answer and add it to -15.

9-15 = -6

The answer is -6

-

-

For the other equation, you also must plug in 3 where ever x is located in the equation.

5/3x -3/5

(5/3)(3) -3/5

Multiply 5/3 and 3

(5/3) x 3 = 5

Take that answer of 5 and add -3/5

5- (3/5) =4 2/5

The answer to this equation would be 4 2/5 or 4.4

5 0
3 years ago
Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
3 years ago
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