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3 years ago

Evaluate 3(x+4)(x+1) (x+2)(x-2) for x=4

Mathematics

2 answers:

EleoNora [17]3 years ago

7 0

Answer:

1440

Step-by-step explanation:

3(x+4)(x+1)(x+2)(x-2)

Let x= 4

3(4+4)(4+1)(4+2)(4-2)

Evaluate each parentheses

3 ( 8) (5)( 6) (2)

Multiply

1440

If you meant

3(x+4)(x+1) = 3(4+4)(4+1) = 3 * 8 *5 = 120

(x+2)(x-2)=(4+2)(4-2) = 6 *2= 12

NemiM [27]3 years ago

5 0

Answer:

1440

Step-by-step explanation:

3(x+4)(x+1)(x+2)(x-2)

3(4+4)(4+1)(4+2)(4-2)

3(8)(5)(6)(2)

1440

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3 years ago

Evaluate 3(x+4)(x+1) (x+2)(x-2) for x=4​

Evaluate 3(x+4)(x+1) (x+2)(x-2) for x=4