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4 years ago

Geometry help please :)

Mathematics

1 answer:

Serhud [2]4 years ago

4 0

The angles of a triangle are right angles

90 = 1/3x + 8

82 = 1/3x

246 = x

Answer is B

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Help on 22 and 23 please

hram777 [196]

Answer:

22.

R= -8, 15

S= -5, 9

T= -8,9

23.

J = 4, 4

K = 4, 3

L = 1, 1

M = 1, 4

Step-by-step explanation:

rotation of -90= y, -x

so R (-7, -5) = -5,7

S (-1, -2) = -2, 1

T (-1, -5) = -5, 1

now we translate 3 left (x-3) and 8 up (y+8)

R (-5, 7) = -8, 15

S (-2, 1) = -5, 9

T (-5, 1) = -8, 9

reflection of x-axis= x, -y

J (-4, 4) = -4, -4

K (-3, 4) = -3, -4

L (-1, 1) = -1, -1

M (-4, 1) = -4, -1

Then a 180° rotation is (-y, -x)

J (-4, -4) = 4, 4

K (-3, -4) = 4, 3

L (-1, -1) = 1, 1

M (-4, -1) = 1, 4

4 0

3 years ago

HELP ASAP!! 5x – 4y = 6 in slope intercept form GIVING BRAINLIEST

crimeas [40]

Answer:

y= 5/4x - 3/2

Hope this helps :)

4 0

3 years ago

What is the volume of the right rectangular prism

Korvikt [17]

Answer:

Step-by-step explanation:

L= L x W x H

L=8x3x5

L=120

3 0

3 years ago

Read 2 more answers

Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the p-value of Z when X = 270.5.