All categories

3 years ago

Again i will give brainllest to the 1st one who solves this!!! 4+4=x solve for x

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

6 0

Answer:

x=8

Step-by-step explanation:

4+4=x

4+4=8

x=8

You might be interested in

The sum of 5 is equal to 8 less than 6 times y

Alisiya [41]

Answer: 5 = 6 -8y

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is -7.08 as a fraction or mixed number

Basile [38]

-7.08 as a fraction would be -177 over 25

3 0

3 years ago

Name the fraction equivalent to 20 over 6

navik [9.2K]

10/3. To find this answer you have to either multiply or divide by a specific number. You choose the number that goes into each of them. In this case I divided by 2 to both the top and bottom number. When I did this I got the answer of 10/3

8 0

2 years ago

Read 2 more answers

Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i

Vsevolod [243]

$\huge \boxed{\mathfrak{Answer} \downarrow}$

$\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\$

Multiply both numerator and denominator of $\sf \frac{5-3i}{-2-9i} \\$ by the complex conjugate of the denominator, -2+9i.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)}) \\$

Multiplication can be transformed into difference of squares using the rule: $\sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$ .

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}}) \\$

By definition, i² is -1. Calculate the denominator.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85}) \\$

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

$\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85}) \\$

Do the multiplications in $\sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right)$ .

$\large \bf \: Re(\frac{-10+45i+6i+27}{85}) \\$

Combine the real and imaginary parts in -10+45i+6i+27.

$\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85}) \\$

Do the additions in $\sf-10+27+\left(45+6\right)i$ .

$\large \bf Re(\frac{17+51i}{85}) \\$

Divide 17+51i by 85 to get $\sf\frac{1}{5}+\frac{3}{5}i \\$ .

$\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i) \\$

The real part of $\sf \frac{1}{5}+\frac{3}{5}i \\$ is $\sf \frac{1}{5} \\$ .

$\large \boxed{\bf\frac{1}{5} = 0.2} \\$

3 0

2 years ago

DinElla’s test grades in her history class are 89, 94, 82, 84, and 98. What score must Ella make on her next test to have a mean

KonstantinChe [14]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers