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Sladkaya [172]
3 years ago
10

What is the length of AB?

Mathematics
2 answers:
vichka [17]3 years ago
7 0

Answer:

The answer is a 6 units

Step-by-step explanation:

sukhopar [10]3 years ago
3 0
I thinks it’s A. 6 units but I’m not sure
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PLEASE ANSWER THIS ITS URGENT
Oksi-84 [34.3K]

Answer:

  • Option C

Explanation:

First, I plotted both the lines on the graph, then I graphed the inequality.<u> </u><em>Please check out image.</em> Looking at the image, we can tell that the graph matches with Graph-C. Hence, Option C is correct.

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2 years ago
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What is x need help asap???
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You will notice that 48°, x, and x lie upon a straight line.  The sum of those angles must then be equal to 180°.  Which means:

48+x+x=180

48+2x=180

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3 years ago
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Find the missing side lengths.
USPshnik [31]
Answer: A, because it is a 30, 60, 90 triangle. To get the 34 they had to times the number by 2 so you divide that by 2 and it gives you 17 then you have the square root of 3* 17, that doesn’t mathematically work so it stays as 17*the square root of 3
6 0
3 years ago
A square with side lengths of 3 cm is reflected vertically over a horizontal line of reflection that is 2 cm below the bottom ed
oksian1 [2.3K]

Answer:

a) 4 cm

b) 5 cm

c) 10 cm

Step-by-step explanation:

The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same.  From there, it is just addition.

Hope it helps <3

5 0
3 years ago
How would you solve these 2 maths problems?
sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = (-2)^{4} + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = (-2)^{4} + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0
3 years ago
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