Question

Square EFGH stretches vertically by a factor of 2.5 to create rectangle E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ? A. (-5, 0) B. (-2, 0) C. (0.5, 0) D. (-2, 2.5)

Answer 1

Answer:

The coordinates of point H' are (-2 , 0) ⇒ answer B

Step-by-step explanation:

* Lets revise the vertical stretch

- A vertical stretching is the stretching of the graph away from the  

 x-axis  

- If k > 1, then the graph of y = k • f(x) is the graph of f(x) vertically

 stretched by multiplying each of its y-coordinates by k

* Lets solve the problem

- Square EFGH stretches vertically by a factor of 2.5 to create

 rectangle E′F′G′H′

∴ k = 2.5

- The square stretches with respect to the x-axis

∴ The square stretches vertically

∴ The y-coordinates of each vertex of the square EFGH are

  multiplied by 2.5 to get the vertices of the rectangle E'F'G'H'

∵ Point H located at (-2 , 0)

∵ The image of point (x , y) after stretched vertically by k is (x , ky)

∴ Point H' located at (-2 , 0 × 2.5) ⇒ (-2 , 0)

∴ The coordinates of point H' are (-2 , 0)

∴ Point H' located at (-2 , 0)