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andreyandreev [35.5K]
3 years ago
7

Square EFGH stretches vertically by a factor of 2.5 to create rectangle E′F′G′H′. The square stretches with respect to the x-axi

s. If point H is located at (-2, 0), what are the coordinates of H′ ? A. (-5, 0) B. (-2, 0) C. (0.5, 0) D. (-2, 2.5)
Mathematics
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

The coordinates of point H' are (-2 , 0) ⇒ answer B

Step-by-step explanation:

* <em>Lets revise the vertical stretch</em>

- A vertical stretching is the stretching of the graph away from the  

 x-axis  

- If k > 1, then the graph of y = k • f(x) is the graph of f(x) vertically

 stretched by multiplying each of its y-coordinates by k

* <em>Lets solve the problem</em>

- Square EFGH stretches vertically by a factor of 2.5 to create

 rectangle E′F′G′H′

∴ k = 2.5

- The square stretches with respect to the x-axis

∴ The square stretches vertically

∴ The <u>y-coordinates</u> of each vertex of the square EFGH are

  multiplied by <u>2.5</u> to get the vertices of the rectangle E'F'G'H'

∵ Point H located at (-2 , 0)

∵ The image of point (x , y) after stretched vertically by k is (x , ky)

∴ Point H' located at (-2 , 0 × 2.5) ⇒ (-2 , 0)

∴ The coordinates of point H' are (-2 , 0)

∴ Point H' located at (-2 , 0)

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