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3 years ago

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You borrowed $25 from your friend. You paid him back in full after 6 months. He charged $2 for interest. What was the annual sim

ple interest rate that he charged you? Use the formula: I = Prt.

2 answers:

Paraphin [41]3 years ago

5 0

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$2\\
P=\textit{original amount}\to& \$25\\
r=rate \\
t=years\to &\frac{1}{2}
\end{cases}$

bearing in mind, "t" is in years, 6months is just 1/2 year

solve for "r", you'd get a decimal amount, multiply times 100, to get the percentage form

TEA [102]3 years ago

4 0

Answer:

Trina borrowed $460 from a friend. Her friend charged her 5% simple annual interest.Let's solve how much will Trina owe her friend in total after 3 years? Use the simple interest formula to solve.

I = prt

I = (460)(0.05)(3)

I = 460 * 0.05 = 23

I = 23 * 3 years = 69 dollars is the interest.

Trina must pay her friend a total of $460 + 69 = 529.

Step-by-step explanation:

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Step-by-step explanation:

Here, the given equation,

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Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

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$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

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$\implies b^2=\frac{3m+2}{10}-----(2)$

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$9b^4=m^2$

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$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

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$(19m+6)(m-6)=0$

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2 years ago

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2 years ago

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