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2 years ago

The sales of digital cameras (in millions of units) in year t is given by the function

Mathematics

2 answers:

erma4kov [3.2K]2 years ago

8 0

Digital Cameras Sold more

ioda2 years ago

3 0

Answer:

Step-by-step explanation:

The function representing the sales of digital cameras (in millions of units) in year t is

f(t) = 3.06t + 6.84 (0 ≤ t ≤ 3)

Also,

The function representing the sales of film cameras (in millions of units) is given by

g(t) = −1.85t + 16.48 (0 ≤ t ≤ 3)

a) where t = 0 corresponds to the end of 2001,

The number of digital cameras sold in 2001 would be

3.06 × 0 + 6.84 = 6.84 digital cameras.

The number of film cameras sold in 2001 would be

−1.85 × 0 + 16.48 = 16.48 film cameras.

Therefore, more film cameras than digital cameras were sold in 2001.

b) 3.06t + 6.84 = −1.85t + 16.48

3.06t + 1.85t = 16.48 - 6.84

4.91t = 9.64

t = 9.64/4.91 = 1.96

Therefore, the sales of digital cameras first exceed those of film cameras at t = 2 and that is in 2003.

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Question 3 options: lily is building a picture frame. the larger rectangle represents the frame. the smaller rectangle represent

Finger [1]

The area of the shaded region of this figure which can be calculated by the difference of the larger region from the smaller region would be 104 in.²

<h3>What is the area of the rectangle?</h3>

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

Area of a larger rectangle

= Length × Width

= 18 × 12

= 216 in.²

Area of the smaller rectangle

Length = 12 - 2 - 2 = 8 in.

Width = 18 - 2 - 2 = 14 in.

= Length × Width

= 8 × 14

= 112 in.²

Area of the shaded region = Area of a larger rectangle - Area of the smaller rectangle

= 216 - 112

= 104 in.²

Hence, the area of the shaded region of this figure is 104 in.²

Learn more about the area;

brainly.com/question/2289492

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2 years ago

1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o

tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

A) If the length of a rectangle was tripled, but the width did not change?

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

B) If the length was tripled and the width was decreased by a factor of 1/4?

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

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2 years ago

2{ 5[12+5 (500 - 100)+399]}

notsponge [240]

This is solved by breaking the equasion down.

2 { 5 [12 + 5 (500 - 100) + 399 ]}

2 { 5 [12 + 5 (400) + 399]}

2 { 5 [12 + 2000 + 399]}

2 { 5 [2411]}

2 {12055}

24110

Is this the answer you were looking for?

3 0

3 years ago

Read 2 more answers

What are the latitude and longitude coordinates of the entrance to the Mount Rushmore parking area?Latitude: 43.8753972, Longitu

Alborosie

Answer:

The answer is already in the question. The coordinates of the entrance to the Mount Rushmore parking area are given by latitude 43.8753972 and longitude -103.4523083.

Step-by-step explanation:

I believe the person asking the question wants some other detail that s/he did not state explicitly.

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3 years ago

What is the greatest common factor of 10x2 + 25x? 15x4

Tanya [424]

Step-by-step explanation:

your answer is 5 the greatest common factor is 5

10= 5

25=5

15= 5

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2 years ago