3.2 - 11(2y + 1) + 4
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The solution to the given non linear system of equation is smallest x value , x = 0 , y = 1 , largest x value x = 3 , y = 8 .
<h3>What is a Equation ?</h3>An Equation is a mathematical statement which relates two algebraic expression with an equal sign in between.
The equations given in the question is
y = 2ˣ
This is an exponential function
-7x +3y = 3
This is a linear function
The equations have been plotted and the solution to the non linear system of equation has been determined
The point at which the graphs intersect is the solution to the system of non -linear equations.
(0,1) and (3,8)
x = 0 , y = 1 ; x = 3 , y = 8
The solution to the given non linear system of equation is smallest x value , x = 0 , y = 1 , largest x value x = 3 , y = 8 .
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Answer:
a) 0.0287 = 2.87% probability that three non-defective components in a batch of seven components.
b) 0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.
Step-by-step explanation:
A sequence of Bernoulli trials composes the binomial distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a selected component is non-defective is 0.8
This means that
a) Three non-defective components in a batch of seven components.
This is P(X = 3) when n = 7. So
0.0287 = 2.87% probability that three non-defective components in a batch of seven components.
b) 8 non-defective components are drawn before the first defective component is chosen.
Now the order is important, so the we just multiply the probabilities.
8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So
0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.