Which equations and/or functions represent the graphed line? Check all that apply.
2 answers:
The picture in the attached figure
step 1
find the equation of the line of the graph
let
A (-4,0) B(0,2)
slope m=(y2-y1)/(x2-x1)------> m=(2-0)/(0+4)----> m=1/2----> m=0.5
with m=0.5 and point B (0,2)
y-y1=m*(x-x1)-----> y-2=(0.5)*(x-0)-----> y=0.5x+2
step 2
find the solution
<span>
a) f(x) = 0.2x - 4----> the </span>function not represent the graphed line<span>
b) f(x) = 0.5x + 2----> </span> the function represent the graphed line<span>
c) f(x) = x + 2</span>--> the function not represent the graphed line<span>
d) y – 3 = (x – 2)---> y=x+1---> </span>the function not represent the graphed line<span>
e) y – 1 = 0.5(x + 2)</span>-----> y=0.5x+1+1---> y=0.5x+2-----> the function represent the graphed line
therefore
the answer is
<span>f(x) = 0.5x + 2
and
</span>y – 1 = 0.5(x + 2)
step 1
find the equation of the line of the graph
let
A (-4,0) B(0,2)
slope m=(y2-y1)/(x2-x1)------> m=(2-0)/(0+4)----> m=1/2----> m=0.5
with m=0.5 and point B (0,2)
y-y1=m*(x-x1)-----> y-2=(0.5)*(x-0)-----> y=0.5x+2
step 2
find the solution
<span>
a) f(x) = 0.2x - 4----> the </span>function not represent the graphed line<span>
b) f(x) = 0.5x + 2----> </span> the function represent the graphed line<span>
c) f(x) = x + 2</span>--> the function not represent the graphed line<span>
d) y – 3 = (x – 2)---> y=x+1---> </span>the function not represent the graphed line<span>
e) y – 1 = 0.5(x + 2)</span>-----> y=0.5x+1+1---> y=0.5x+2-----> the function represent the graphed line
therefore
the answer is
<span>f(x) = 0.5x + 2
and
</span>y – 1 = 0.5(x + 2)
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Check the picture below.
segments AC and BC are equal, that means that ABC is an isosceles triangle, with twin sides. Now the twin sides make twin angles on the opposite side, namely the angles at A and B are twins.
if the angles at A and B are twins, and CD is ⟂ to AB, there's only one possibility that can happen, and is if CD is an angle bisector at C.
an angle bisector like CD with twin angles on each side, will cut AB in two equal halves, therefore, if AB = 4, then AD = 2 and DB = 2.
segments AC and BC are equal, that means that ABC is an isosceles triangle, with twin sides. Now the twin sides make twin angles on the opposite side, namely the angles at A and B are twins.
if the angles at A and B are twins, and CD is ⟂ to AB, there's only one possibility that can happen, and is if CD is an angle bisector at C.
an angle bisector like CD with twin angles on each side, will cut AB in two equal halves, therefore, if AB = 4, then AD = 2 and DB = 2.
