∠DCE = ∠BAE because of alternate interior ∠s
∠CDE = ∠ABE because of alternate interior ∠s
Triangle DCE is congruent to Triangle BAE because of ASA
AE = CE because of CPCTC
BE = DE because of CPCTC
Answer:
the first graph
Step-by-step explanation:
The first one - y = 1/4x + 3/2.
sorry im a bit late but hopefully this helps
Part A)The given equation is:

The radicand or discriminant(d) of the equation will be:

Since the discriminant is equal to 0, the given quadratic equation has only 1 root. In other words we can say the the given equation is a perfect square.
Part B)The given equation is:

We can solve this expression by factorization. Factors of middle term are to be made in such a way that their product equals the product of first and third term and sum is equal to the middle term i.e. product should be 4x² and sum should be -4x.
So the two such terms are -2x and -2x. Using the factors and simplifying the equation by taking common we get:
V=u + at
V - u = at divide both sides by
t
(V-u)/t =a
a = (v - u) /t
Answer:
x = -3/5
Step-by-step explanation:
y = 10x + 6
0 (- 6) = 10x + 6 (- 6)
-6/10 = 10x/10
-6/10 = x
-3/5 = x