Given:
A line passes through the two points (3,5) and (-1,1).
To find:
The equation of the line in fully reduced point-slope form.
Solution:
If a line passes through two points, then the point slope form of the line is
![y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
The line passes through the two points (3,5) and (-1,1). So, the point slope form of the line is
![y-5=\dfrac{1-5}{-1-3}(x-3)](https://tex.z-dn.net/?f=y-5%3D%5Cdfrac%7B1-5%7D%7B-1-3%7D%28x-3%29)
![y-5=\dfrac{-4}{-4}(x-3)](https://tex.z-dn.net/?f=y-5%3D%5Cdfrac%7B-4%7D%7B-4%7D%28x-3%29)
![y-5=1(x-3)](https://tex.z-dn.net/?f=y-5%3D1%28x-3%29)
Therefore, the point slope form of the line in fully reduced form is
, here 1 is the slope of the line.
Answer: 5*2*2*3*3
Step-by-step explanation:
First you divide 180 by 2 and you get 90. Then you proceed to divide that by 2 again and get 45. You will then divide 45 by 3 to get 15. Then divide 15 by 3 again and get 5, which cannot be divided any smaller.
180/2=90
90/2=45
45/3=15
15/3=5
Answer:
A. (f + g)(1) = - 9
B. (f - g)(0) = -7
C. (fg)(3) = 0
Step-by-step explanation:
A. (f + g)(1) = f(1) + g(1) f(1) = 1^2 - 9 = 1 - 9 = - 8 g(1) = 1 - 2 = - 1
= -8 -1 = -9
B. (f - g)(0) = f(0) - g(0) f(0) = 0^2 - 9 = 0 - 9 = -9 g(0) = 0 - 2 = -2
= -9 + 2 = -7
C. (fg)(3) = f(3)(g(3) f(3) = 3^2 - 9 = 9 - 9 = 0 g(3) = 3 - 2 = 1
= 0(1) = 0
Angle is 90 degrees, so five-thirds of a right angle is 90*5/3=450/3=150 degrees.
Answer:
20
Step-by-step explanation:
Divisors of 100
1, 2, 4, 5, 10, 20, 25, 50, 100