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3 years ago

Which One Doesn't Belong? Why? A

Mathematics

2 answers:

denis23 [38]3 years ago

6 0

C doesn’t belong because it has rounded edges. all the other options have vertices

Arisa [49]3 years ago

6 0

Maybe C because it doesn’t have any straight lines or A because it has all equal faces

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a rectangle has an area of 54 square inches the width of the rectangle is 9 inches what is the langth

STatiana [176]

Answer:

As per Provided Information

Area of rectangle is 54 square inches
Width of the rectangle is 9 inches.

We have to calculate the length of rectangle .

As we know the formula to find the Area of rectangle .

$\boxed{\bf \: Area_{(Rectangle)} = length \: \times width}$

On substituting the value we obtain

$\sf \qquad \: \longrightarrow 54 = length \times 9 \\ \\ \\ \sf \qquad \: \longrightarrow \cfrac{54}{9} = length \\ \\ \\ \sf \qquad \: \longrightarrow \: length \: = \cfrac{54}{9} \\ \\ \\ \sf \qquad \: \longrightarrow \: length \: = \cancel \cfrac{54}{9} \\ \\ \\ \sf \qquad \: \longrightarrow \: length \: = 6 \: inches$

Therefore,

Length of the rectangle is 6 inches .

8 0

2 years ago

Check/correct my work please! Working with polynomials and stuff.

OLEGan [10]

1. (b+2)(b+2)=b^2 +4b + 4 (FOIL)
2. FOIL; x^2 + 6x + 9
3. correct

8 0

3 years ago

What could the answer be?

VashaNatasha [74]

Answer:

it 66

Step-by-step explanation:

8 0

3 years ago

(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28

Veronika [31]

$(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}$

4 0

4 years ago

Read 2 more answers

If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)

svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

4 0

3 years ago

Which One Doesn't Belong? Why? A​

Which One Doesn't Belong? Why? A