Answer: use photomath
Step-by-step explanation:
Answer:(6,-2)
Step-by-step explanation:
M is the midpoint of AB then ,
M =
,
,
,
so, B= (6,-2)
Let x = number of lines
x/3 = r2 2,5,8,11,14,17,20,23,26,29,32,35,38,41,44,47
x/5 = r2 2,7,12,17,22,27,32,37,42,47
x/7 = r5 5,12,19,26,33,40,47
47 is the smallest number that fits all 3 requirements.
Answer: False, it's <u>not</u> a solution
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Explanation:
Replace every copy of c with 12. Then simplify.
4c - 2 > 46
4*12 - 2 > 46
48 - 2 > 46
46 > 46 ... false
The statement is false because there isn't a number that's larger than itself (or smaller than itself).
Since the last statement is false, this means the first inequality is false when c = 12.
Therefore, c = 12 is <u>not</u> a solution.
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Another approach:
Let's isolate c in the original inequality.
4c - 2 > 46
4c > 46+2
4c > 48
c > 48/4
c > 12
The solution set consists of numbers larger than 12. We leave 12 itself out of the solution set.
This is because c > 12 would be 12 > 12 which is false.