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Reika [66]
3 years ago
5

What set of reflections would carry triangle ABC onto itself?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0
Answer will be abcd
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kodGreya [7K]
1 by 120
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4 by 30
5 by 24
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Any help please thank u
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Dude why did you scible on top of the the choices 
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3 years ago
Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr
NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Distance between B(0, 5) and C(4, 2):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(0, 5) = (x_1, y_1)

C(4, 2) = (x_2, y_2)

BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}

BC = \sqrt{(4)^2 + (-3)^2}

BC = \sqrt{16 + 9} = \sqrt{25}

BC = 5 units

Distance between C(4, 2) and D(1, -2)

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(4, 2) = (x_1, y_1)

D(1, -2) = (x_2, y_2)

CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}

CD = \sqrt{(-3)^2 + (-4)^2}

CD = \sqrt{9 + 16} = \sqrt{25}

CD = 5 units

Distance between E(-2, -2) and F(-5, 2):

EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

E(-2, -2) = (x_1, y_1)

F(-5, 2) = (x_2, y_2)

EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}

EF = \sqrt{(-3)^2 + (4)^2}

EF = \sqrt{9 + 16} = \sqrt{25}

EF = 5 units

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0
3 years ago
Tell whether the sequence is arithmetic if it is identify the common difference. -7, -3, 1, 5
Oxana [17]

Step-by-step explanation:

If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence.

d=-7+3=-3-1=1-5=-4

so it is an arithmetic sequence

hope it helps

7 0
3 years ago
Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the shape of the grap
Kamila [148]
For a polyonomial
P(x)=ax^n+bx^(n-1)...zx^0
when n is odd, the endpoints of the graph point in oposite directions
when n is even, the endpoints of the graph point in same direction

a is the leading term
when a is positive and:
1. n is odd, the graph goes from bottom left to top right
2. n is even, the graph goes from top left to top right

when a is negative and:
1. n is odd, the graph goes from top left to bottom right
2. n is even, the graph goes from bottom left to bottom right



xintercept is where the line crosses the x axis or when y=0
yintercept is where the line crosses the y axis or when x=0




f(x)=1x^3-11x^2+36x-36
leading term is positive and odd degree

graph goes from bottom left to top right, has 1 inflection point

yint, sub 0 for all x's
f(0)=0^3-11(0)^2+36(0)-36
yintercept is y=-36 or (0,-36)

xintercept
set function equal to zero
0=x^3-11x^2+36x-36
factor
0=(x-2)(x-3)(x-6)
x=2,3,6
xintercepts are at x=2,3,6 or (2,0), (3,0) and (6,0)
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3 years ago
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