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4 years ago

Question 4 (1 point)

Chemistry

1 answer:

bagirrra123 [75]4 years ago

5 0

Answer:

Argon

Explanation:

The element that would most likely be a good substitute for neon is "argon".

These two elements belong to the noble gases in Group 18(8A) of the Periodic Table. They are inert gases - they do not react chemically with other substances.

Argon, as an inert gas is often used whenever an inert atmosphere is needed. Argon is used in incandescent light bulbs. It is used to stop oxygen from corroding the filament. It is also used by welders to protect weld area.

Argon is a good substitute for neon in this context because they possess some physical properties which are similar.

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Considering that the mantle is 44.8% oxygen and 21.5% silicon by mass, calculate the mole ratio of oxygen atoms to silicon atoms

horrorfan [7]

The mantle has a mass of around $4.278 X 10 ^2^4 kg$ that is around 68.4% of earth's mass.

So to calculate moles we need to first find out the mass of oxygen and silicon present in mantle. It is given that oxygen is 44.8% by mass in mantle and 21.5% by mass in mantle, therefore to calculate its mass, we need to use $\text{mass percentage }=\frac{\text{mole of solute}}{\text{mass of solution}}\times100$

Now, to calculate mass percentage of oxygen

$44.8 =\frac{x}{4.278X10^2^4kg}\times100$

$x= 191.65\times10^2^2kg$

Similarly the mass of silicon can be calculated

$21.5 =\frac{x}{4.278X10^2^4kg}\times100$

$x=91.977\times10^2^2kg$

Now, the moles of any substance is calculated by

$\text{moles}= \frac{\text{given mass}}{\text{molar mass}}$

$\text{moles of oxygen}= \frac{191.65\times10^2^2kg}{2.6566962\times10^-^2^6kg}$

where, mass of oxygen in kilograms is $2.6566962\times10^-^2^6kg$

So, $\text{moles of oxygen}=72.1384\times10^4^8\text{moles of O}$

Similarly $\text{moles of silicon}= \frac{91.977\times10^2^2kg}{4.663\times10^-^2^6kg}$

$\text{moles of silicon}=19.724\times10^4^8\text{moles of Si}$

Now, to calculate mole ratio we need to divide every moles to the lowest calculated mole that is the moles of Si and round it off to the nearest whole number.

$\text{mole ratio of oxygen}= \frac{72.138\times10^4^8kg}{19.724\times10^4^8kg}$

$=3.65\approx 4$

$\text{mole ratio of Silicon}=\frac{19.724\times10^4^8}{19.724\times10^4^8}$

$=1$

$\text{Mole ratio of Oxygen : Mole ratio of Silicon} = 4:1$

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4 years ago

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How many electrons are transferred in the ionic bond between sodium and chlorine in NaCl?

Alexxx [7]

Answer:

Explanation:

since Na has one electron in its outer shell it has to give away that one electron in order to obtain a noble gas structure and chlorine needs to obtain one electron also to became a noble gas so it receives the electron that the sodium gave away.

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3 years ago

Name the compound containing only fluorine and hydrogen.

Sonbull [250]

Hydrogen has only one electron. It has one proton of nucleus and one outter electron.

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3 years ago

What is a dipeptide and a peptide bond?

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A polypeptide is a peptide composed of two amino-acid and a peptide bond is a chemical bond formed between two molecules, when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water.

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3 years ago

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A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3

IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cl₂: 4 moles
P: 2 moles
PCl₃: 1 mole
PCl₅: 1 mole

The molar mass of the compounds is:

Cl₂: 70.9 g/mole
P: 31 g/mole
PCl₃: 137.35 g/mole
PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
P: 2 moles× 31 g/mole= 62 grams
PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

$mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}$

mass of Cl₂= 96.97 grams

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

$mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}$

mass of PCl₃= 38.26 grams

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

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