Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)
Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
14 - pHi - log 2 = 14 - pH
In terms of pHi,
pH = pHi + log 2
Answer:
we can do it again and again and again and again and again and again
It’s halfway into the circle, you would need it when trying to find the circumference
0.2 g/mL
We can use the density formula <em>D = M/V</em>.
<em>D</em> = 6 g/30.0 mL = 0.2 g/mL
Answer:
Si
Explanation:
The outer shells of both elements have 4 electrons
