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3 years ago

What is the valence electron of manganese?

Chemistry

2 answers:

DIA [1.3K]3 years ago

6 0

Answer:

25th electron

Explanation:

the last electron is the valence electron. Assuming it has equal numbers of protons and electrons, then the 25th electron is the valence.

patriot [66]3 years ago

6 0

Answer: [Ar] 3d5 4s2

Explanation:

Manganese is a transition metal, meaning that it can have more than one valence state. Its electron configuration is [Ar] 3d5 4s2. The two electrons in the 4s orbital are obvious valence electrons, so a valence state of 2+ is possible.

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When a test instrument is calibrated, does its accuracy, precision, or reliability improve?

My name is Ann [436]

The answer is accuracy.

That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.

The other factor will not be improved that is its reliability and precision remains the same.

So the answer is accuracy is improved when a test instrument is calibrated.

8 0

4 years ago

Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati

ollegr [7]

Explanation:

Let us assume that the given data is as follows.

mass of barium acetate = 2.19 g

volume = 150 ml = 0.150 L (as 1 L = 1000 ml)

concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

$Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}$

Hence, moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times Ba(C_{2}H_{3}O_{2})_{2}$ .......... (1)

As, No. of moles = $\frac{mass}{\text{molar mass}}$

Hence, moles of $Ba(C_{2}H_{3}O_{2})_{2}$ will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{2.19 g}{255.415 g/mol}$ (molar mass of $Ba(C_{2}H_{3}O_{2})_{2}$ is 255.415 g/mol)

= $8.57 \times 10^{-3}$

Moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times 8.57 \times 10^{-3}$

= 0.01715 mol

Hence, final molarity will be as follows.

Molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.01715 mol}{0.150 L}$

= 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

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3 years ago

Less energy was entering Earth's

ololo11 [35]

Answer:

The temperatures on Earth increase

Explanation:

more energy results in more heat.

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3 years ago

A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g).

katen-ka-za [31]

Answer:

Ratio of Vrms of argon to Vrms of hydrogen = 0.316 : 1

Explanation:

The root-mean-square speed measures the average speed of particles in a gas, and is given by the following formula:

Vrms = $\sqrt{3RT/M}$

where R is molar gas constant = 8.3145 J/K.mol, T is temperature in kelvin, M is molar mass of gas in Kg/mol

For argon, M = 40/1000 Kg/mol = 0.04 Kg/mol, T = 4T , R = R

Vrms = √(3 * R *4T)/0.04 = √300RT

For hydrogen; M = 1/1000 Kg/mol = 0.001 Kg/mol, T = T, R = R

Vrms = √(3 * R *T)/0.001 = √3000RT

Ratio of Vrms of argon to that of hydrogen = √300RT / √3000RT = 0.316

Ratio of Vrms of argon to that of hydrogen = 0.316 : 1

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4 years ago

What are the names of the elements which are gases in the air

Yakvenalex [24]

The molecules of two different elements, nitrogen and oxygen, make up about 99 percent of the air.

have a good day !! :)

6 0

3 years ago

Read 2 more answers

What is the valence electron of manganese?​

What is the valence electron of manganese?