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n200080 [17]
4 years ago
15

Dr. Young is a coastal plant ecologist studying symbiotic root nodule-forming bacteria that must be present in soils on the East

ern Shore of Virginia in order for woody plants to grow. Dr. Young is studying how these bacteria are dispersed over a coastal barrier island and hypothesizes that bird droppings may transport the bacteria to young soils either locally or long-distance.
To test this hypothesis, you germinate two hundred sterile shrub seedlings, each of which you then assign to one of the following treatments to test for nodule development (successful bacterial infection):
Treatments were as follows:
PR: Positive Reference; crushed nodules
NR: Negative Reference; distilled water
BI: Barrier Island field-collected bird dropping suspension
ML: Mainland-collected bird dropping suspension
For this experiment, the null and alternative hypothesis are:
A: Nodulation is independent of seedling treatment
B: Nodulation is related to (not independent of) seedling treatment
C: Nodulation is correlated to bird dropping exposure.
D: There is no difference between exposure to mainland or island bird droppings
Mathematics
1 answer:
saul85 [17]4 years ago
6 0

Answer:

Option A

Step-by-step explanation:

The null hypothesis would be that: Nodulation is independent of seedling treatment which includes all treatment (PR, NR, BI and ML)

While the alternative smoothies would be that there is a relationship/an association between Nodulation and all the treatments.

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a cheap way to go about it is, let's do away with the denominators, and we'll do so by simply multiplying both sides by the the LCD of all fractions, in this case, that'd be "ab", so we multiply both sides by "ab".


\bf \cfrac{1}{a}+\cfrac{1}{b}=c\implies\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{ab}}{ab\left( \cfrac{1}{a}+\cfrac{1}{b} \right)=ab(c)}\implies b+a=abc \\\\\\ a=abc-b\implies a=\stackrel{\textit{common factor}}{b(ac-1)}\implies \cfrac{a}{ac-1}=b

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3 years ago
Tell me the answer of this
Harrizon [31]
<em>The answer you are looking for is: </em>
<em><u>\frac{3}{2} </u></em>
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4 0
3 years ago
The area of a triangular flag is 132 square centimetres. Its altitude is 2 centimetres longer than twice its base. Find the leng
Anika [276]

Answer:

24 cm and 11 cm

Step-by-step explanation:

GIVEN: The area of a triangular flag is 132 \text{ cm}^2. Its altitude is 2\text{ cm} longer than twice its base.

TO FIND: lengths of the altitude and the base.

SOLUTION:

Let the altitude and the base of flag be a and b

According to the question

a=2+2b

area of triangle =\frac{1}{2}\times base \times alltitude=\frac{1}{2}a\times b

\implies \frac{1}{2}(2b+2)b=132 \Rightarrow 2b^2+2b-264

Solving equation we get

b=11   then a=24

Hence the lengths of altitude and base of triangular flag is 24 cm and 11 cm respectively.

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Answer:

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Step-by-step explanation:

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