2x - 20 = 32
2x - 20 + 20 = 32 + 20
2x = 52
/2 = /2
x = 26
Answer:
As follows, (shortened)
Step-by-step explanation:
1.AB=CD (Given)
2.AB+BC=CD+BC ( By additive property, adding BC to both sides)
3.AB+BC=CD+DE (Given, BC=DE, By substitution property replacing BC by DE)
4.AC=CE(By segment addition, and substitution property)
Answer:
1st problem:
-1, 2i, -2i
Set the function equal to 0 and divide for x
0=x^3+x^2+4x+4
Subtract 4 from both sides leaving you with
-4=x^3+x^2+4x
divide both sides by four
-4÷4= -1
That is how you get -1
you now have -1=x^2+x^3+x
Solve for x buy finding the square roots of x^2, x^3 and subtracting x from both sides and you get 2i, -2i
Your answer to number one is -1, 2i, -2i
Second problem:
Find the LCD to be able to add these first
The LCD of (x-4)/x^2-2x is
x(x-2)
That is the first side done
The second side's LCD is (x+2)(x-2)
Now you can add the two together
x(x-2)+(x+2)(x-2)=
Your answer in fraction form is
(x+4)/x(x+2)
Answer:
a = 6
Step-by-step explanation:
Area = 36
Only one number will make this missing length true.
Obviously it's a square so one number x one number will equal to 36
6 x 6 = 36
(x - 5)^2 = 9
(x - 5)(x - 5) = 9
x^2 - 10x + 25 = 9
x^2 - 10x + 25 - 9 = 0
x^2 - 10x + 16 = 0
(x - 8)(x - 2) = 0
x - 8 = 0
x = 8
x - 2 = 0
x = 2
solution : x = 8 and x = 2